如将字符串 "i am a student."翻转后的结果应该为"student. a am i"

 思路：先翻转整个句子，再翻转句子中的单词

两次翻转达到结果（i am a student.）-(.tneduts a ma i)- (student. a am i)

// 思路：先翻转整个句子，再翻转句子中的单词// 两次翻转达到结果（i am a student.）-(.tneduts a ma i)-// (students a am i)public static void main(String[] args) {	String word = "i am a student.";	System.out.println("原始字符串："+word);	// 1、翻转整个句子	String resultWord=reverse(word.toCharArray());	System.out.println("翻转整个句子后字符串："+resultWord);	// 2、翻转句子中的每个单词	String[] array=resultWord.split(" ");	System.out.println("翻转句子中每个单词后的字符串：");	for (int i = 0; i < array.length; i++) {		array[i]=reverse(array[i].toCharArray());		System.out.print(array[i]+" ");	}}/* * 翻转句子 */private static String reverse(char[] word) {	if (word == null || "".equals(word)) {		return null;	} else {		int start = 0;		int end = word.length - 1;		int middle = (start + end) / 2;		char temp = ' ';		while (start <=middle && end >= middle) {			temp = word[start];			word[start] = word[end];			word[end] = temp;			start++;			end--;		}	}	return new String(word);}